(x^2-x-20)(x+1)/(x^2+5x+4)(x+5)

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Solution for (x^2-x-20)(x+1)/(x^2+5x+4)(x+5) equation: 


D( x )

x^2+5*x+4 = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

DELTA = 5^2-(1*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-5)/(1*2) or x = (-9^(1/2)-5)/(1*2)

x = -1 or x = -4

x in (-oo:-4) U (-4:-1) U (-1:+oo)

(((x^2-x-20)*(x+1))/(x^2+5*x+4))*(x+5) = 0

((x^2-x-20)*(x+1)*(x+5))/(x^2+5*x+4) = 0

x^2-x-20 = 0

x^2-x-20 = 0

DELTA = (-1)^2-(-20*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)+1)/(1*2) or x = (1-81^(1/2))/(1*2)

x = 5 or x = -4

(x+4)*(x-5) = 0

x^2+5*x+4 = 0

x^2+5*x+4 = 0

DELTA = 5^2-(1*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-5)/(1*2) or x = (-9^(1/2)-5)/(1*2)

x = -1 or x = -4

(x+4)*(x+1) = 0

((x+4)*(x-5)*(x+1)*(x+5))/((x+4)*(x+1)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+4 )

x+4 = 0 // - 4

x = -4

( x+5 )

x+5 = 0 // - 5

x = -5

( x-5 )

x-5 = 0 // + 5

x = 5

x in { -1} 

x in { -4} 

x in { -5, 5 }

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